SOLUTION: i know its already solved but i need to know how to prove it 6log base 6^(3x-1)= (3x-1) thanks a bunch!

Question 38872: i know its already solved but i need to know how to prove it
6log base 6^(3x-1)= (3x-1)
thanks a bunch!
Answer by DavidChandler(2) (Show Source): You can put this solution on YOUR website!
I think the problem you are trying to state is:
6^[log base 6 of (3x-1)]= (3x-1)
The exponential function and log function (for any base) are inverse functions of each other. Therefore applying one then the other brings you back where you started. In this case you start with te expression (3x-1), take its base 6 log, then plug the result into the base 6 exponential function. The two steps cancel each other out. It's like adding 2 then subtracting 2, or doubling then halving. Inverse functions "undo" each other.
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