SOLUTION: log(7x+1)=log(x-2)+ 1
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Question 387834
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log(7x+1)=log(x-2)+ 1
Answer by
ewatrrr(24785)
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Hi,
log(7x+1)-log(x-2)= 1
10^1 = (7x+1)/(x-2)
10(x-2) = 7x+1
10x -20 = 7x + 1
3x = 21
x = 7
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