SOLUTION: solve each equation. If the answer is not exact give the answer to 4 decimal places.
3^(x+3)+3^x=84
4^(x+2)-4^x=15
Algebra.Com
Question 384403: solve each equation. If the answer is not exact give the answer to 4 decimal places.
3^(x+3)+3^x=84
4^(x+2)-4^x=15
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
One way to solve this involves factoring in a way you may not have seen/done before. The first term on the left is the product of x+3 3's. The second term is the product of x 3's. So both terms have x 3's in common. We can factor out those x 3's from each term. After we factor out the x 3's, the first term will still have 3 3's. The second term will just be a 1 since we factored out all of its 3's:
which simplifies to:
Dividing both sides by 28 we get:
So x = 1
This problem can be solved in a similar way:
And so, if you remember how zero exponents work, x = 0.
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