SOLUTION: Seeing as I don't even know where to begin this is an extremely difficult question for me. The gravitational force on an object (or weight) varies inversely to the square of the

Question 382904: Seeing as I don't even know where to begin this is an extremely difficult question for me.
The gravitational force on an object (or weight) varies inversely to the square of the distance the object from the center of the Earth. An object weighs 430 pounds when it is on the surface of the Earth, which means the object is 3960 miles from the center of the earth.
a) calculate the value of k.
b) determine the weight of the object, to the nearest pound, when it is 230 miles ABOVE the Earth's surface.
so i know to start with something like y=k/w^2
I think??
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The gravitational force on an object (or weight) varies inversely to the square of the distance the object from the center of the Earth.
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f = k/d^2
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An object weighs 430 pounds when it is on the surface of the Earth, which means the object is 3960 miles from the center of the earth.
a) calculate the value of k.
430 = k/3960^2
k = 430*3960^2 = 6743088000
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b) determine the weight of the object, to the nearest pound, when it is 230 miles ABOVE the Earth's surface.
f = (673088000)/(3960+230)^2
f = 384.09 lbs
----------------------------
Cheers,
Stan H.
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