SOLUTION: Please help me with this problem: {{{6e^(-x)=3}}}
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Algebra: Exponent and logarithm as functions of power
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Question 38177
This question is from textbook
Heath Algebra 2 An Integrated Approach
:
Please help me with this problem:
This question is from textbook
Heath Algebra 2 An Integrated Approach
Answer by
fractalier(2101)
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Okay, from 6e^(-x) = 3
we'll divide by 6 first and get
e^(-x) = 1/2
then take the ln of both sides
ln[e^(-x)] = ln(1/2)
-x = ln(1/2)
x = -ln(1/2)
x = ln 2