Hi,

Solving









10^0 = [(x-6)(x+3)]/22

1 = [(x-6)(x+3)]/22

22 = (x-6)(x+3)

22 = x^2 -3x - 18

0 = x^2 -3x - 40

factoring

(x-8)(x+5)= 0

(x+5) = 0

x = -5  extraneous solution

(x-8)=0

x = 8 

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