# SOLUTION: Not sure on how to go about this problem. 4(Exponet 2x)=9(exponet x-1). solve for x

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 Algebra: Exponent and logarithm as functions of power Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Exponential-and-logarithmic-functions Question 36852: Not sure on how to go about this problem. 4(Exponet 2x)=9(exponet x-1). solve for xAnswer by stanbon(57347)   (Show Source): You can put this solution on YOUR website!4(Exponet 2x)=9(exponet x-1). solve for x 4^(2x) = 9^(x-1) Take the log of both sides to get: (2x)(log4) = (x-1)(log9) 2xlog4=xlog9-log9 2xlog4-xlog9=-log9 x(2log4-log9)=-log9 x(0.24987747) = -0.95424251 x=-3.81884173... Cheers, Stan H. Comment: There are many other ways to solve this problem. Your instructor may have used a different method.