SOLUTION: express the logarithm in terms of log2 M and log2 N: log2 cube root of M^2N
Algebra.Com
Question 36249: express the logarithm in terms of log2 M and log2 N: log2 cube root of M^2N
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
log_2 (cbrt (M^2N)) =
(1/3)*(log_2 (M^2N)) =
(1/3)*(log_2 M^2 + log_2 N) =
(1/3)*(2*log_2 M + log_2 N) =
(2/3)*log_2 M + (1/3)*log_2 N
RELATED QUESTIONS
express the logarithm in terms of log2 M and log2 N: log2 cube root of... (answered by stanbon)
Express the logarithm in terms of log2M and log2N:
log2 (M/N)7
(answered by ewatrrr,Theo)
Please help me solve this:
Given that log2 3 = m and log2 5 = n, express log2 0.3 in... (answered by josgarithmetic,math_helper,MathTherapy)
Express as a logarithm of a single number or expression
log2 M + log2 N + 3
(answered by josgarithmetic)
given that log2 =m and log 3 = n express log 20 in terms of m and... (answered by jsmallt9)
if log7 = m and log5 = n write the following in terms of n and m
a) log3500... (answered by greenestamps,Boreal)
Express the logarithm in terms of log2M and log2N:... (answered by lwsshak3)
Given that log2 3=x, log2 5 = y,and log2 7=z,express logx square root 21 in terms of... (answered by greenestamps,MathLover1,Theo,ikleyn,Edwin McCravy)
Convert log4.5 in the terms of log2 and... (answered by lwsshak3)