SOLUTION: Solve for x: (1/8) to the 2x-1 (2x-1 is the exponent) = 8 to the x-1 (x-1 is the exponent.

Algebra.Com
Question 35518: Solve for x: (1/8) to the 2x-1 (2x-1 is the exponent) = 8 to the x-1 (x-1 is the exponent.
Found 2 solutions by Nate, Prithwis:
Answer by Nate(3500)   (Show Source): You can put this solution on YOUR website!
(1/8)^(2x-1) = (8)^(x-1)
(8^(-1))^(2x-1) = (8)^(x-1)
(8)^(-2x+1)=8^(x-1)
-2x + 1 = x - 1
-3x = -2
x = 2/3

Answer by Prithwis(166)   (Show Source): You can put this solution on YOUR website!
(1/8)^(2x-1) = (8)^(x-1)
(8^(-1))^(2x-1) = (8)^(x-1)
(8)^(-2x+1)=8^(x-1)
-2x + 1 = x - 1
-3x = -2
x = 2/3

RELATED QUESTIONS

Solve (2x+1 is the exponent)... (answered by stanbon)
Solve the equation for x: 2 to the 3x (3x is the exponent) = 3 to the 2x+1 (2x+1 is the... (answered by rapaljer)
what is the answer to this problem, x exponent 3 y exponent -3 divide (xy) exponent... (answered by jsmallt9)
What is 1/y to the exponent of 8 times y to the exponent of... (answered by Fombitz)
How do you solve 2 to the exponent... (answered by mathslover)
Solve for the exponent 3^x+1 =... (answered by jim_thompson5910)
What is 4 to the -1 exponent? (answered by nerdybill,Edwin McCravy)
I really need help with this, I've been given the rules, but I don't under stand how to... (answered by Mathtut,josmiceli)
solve for x using trigonometry for the interval [0, 2π) sin^2x= 1/2 The x after... (answered by KMST)