SOLUTION: log(base 4)(x-9)=2
log(base 4)z + log(base 4)(z-3)=1
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Question 353233: log(base 4)(x-9)=2
log(base 4)z + log(base 4)(z-3)=1
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Hi,
log(base 4)(x-9)=2
 \ \ \Rightarrow\ \ b^y = x)
x = 25
.
log(base 4)z + log(base 4)(z-3)=1
 )
.
= 1)
(z - 4)(z + 1) = 0
.
z = -1 & 4
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