SOLUTION: Compare equations y=log5x(the 5 is at the bottom next to the g) & y=5^x; y=log1/3x(the 1/3 is low next to the g) & y=(1/3)^x; y=log5x & y=log(1/3)x (both the 5 and 1/3 are low next

Question 349105: Compare equations y=log5x(the 5 is at the bottom next to the g) & y=5^x; y=log1/3x(the 1/3 is low next to the g) & y=(1/3)^x; y=log5x & y=log(1/3)x (both the 5 and 1/3 are low next to the g)
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!

(Note: The right side is called "the base 5 log of x".)

If we rewrite the first equation in exponential form we get:

These two equation are identical except the x's and y's have traded places. This makes the two equations inverses of each other.

Again, if we rewrite the first equation in exponential form we get:

Again we have inverses.

Other than these both being logarithmic functions, there is no special relationship between these two equations.
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