# SOLUTION: "SOLVING EXPONENTIAL AND LOGARITHMIC EQUATIONS" ---> why is it that when any value of X results in a log of a negative number, it must be rejected??? it's from a workbook that

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: "SOLVING EXPONENTIAL AND LOGARITHMIC EQUATIONS" ---> why is it that when any value of X results in a log of a negative number, it must be rejected??? it's from a workbook that       Log On

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 Algebra: Exponent and logarithm as functions of power Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Exponential-and-logarithmic-functions Question 34700: "SOLVING EXPONENTIAL AND LOGARITHMIC EQUATIONS" ---> why is it that when any value of X results in a log of a negative number, it must be rejected??? it's from a workbook that my professor created - not a textbook.Answer by stanbon(60771)   (Show Source): You can put this solution on YOUR website!Consider an example log (-10) = x The exponential meaning of this is 10^x=-10 But no power of 10 can produce a negative number. Oh? What if we make the base -10 ? Then (-10)^1 = -10 so, -10 works for this case; but what about (-10)^(1/2). That is imaginary. Negative bases just don't give the properties that log functions need. So the base must be positive and its powers can never be negative. Cheers, Stan H.