SOLUTION: By using the formula logba = (log a)/(log b) where the b is lowered solve log2 10000 where the two is lowered Thank you in advance for your help.

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: By using the formula logba = (log a)/(log b) where the b is lowered solve log2 10000 where the two is lowered Thank you in advance for your help.      Log On


   

Question 33208: By using the formula logba = (log a)/(log b) where the b is lowered solve log2 10000 where the two is lowered
Thank you in advance for your help.
Answer by mukhopadhyay(490) About Me  (Show Source):
You can put this solution on YOUR website!
log (base2) 10000 = (log 10000)/(log 2) = (log 10^4)/(log 2) = 4/(log 2)