SOLUTION: I need to solve this and round it to the nearest thousandth. 6^(2-m)=2^(3m+1) I am hoping I have it written right. Trying to write it on here is confusing me with this one.

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: I need to solve this and round it to the nearest thousandth. 6^(2-m)=2^(3m+1) I am hoping I have it written right. Trying to write it on here is confusing me with this one.       Log On


   

Question 330200: I need to solve this and round it to the nearest thousandth.
6^(2-m)=2^(3m+1)
I am hoping I have it written right. Trying to write it on here is confusing me with this one. I know the answer is .747
Thanks
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Always verify with your original equation.
6%5E%282-m%29=2%5E%283m%2B1%29
6%5E%282-0.747%29=2%5E%283%280.747%29%2B1%29
6%5E%281.253%29=2%5E%283.241%29
9.44=9.45
Yes, that's a good solution.