SOLUTION: Please show work: Divide (fraction 1) (3y^2-12)/(^2+4y+4) / (y^3-2y^2)/(y^2+2y) (fraction 2)

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Please show work: Divide (fraction 1) (3y^2-12)/(^2+4y+4) / (y^3-2y^2)/(y^2+2y) (fraction 2)      Log On


   

Question 318214: Please show work:
Divide
(fraction 1) (3y^2-12)/(^2+4y+4) / (y^3-2y^2)/(y^2+2y) (fraction 2)
Answer by mananth(16946) About Me  (Show Source):
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(3y^2-12)/(y^2+4y+4) / (y^3-2y^2)/(y^2+2y)
..
3(y^2-4)/(y+2)^2 / y^2(y-2)/y(y+2)
..
3(y+2)(y-2) /(y+2)^2 * y(y+2)/y^2(y-2)
..
3(y+2)(y-2)*y(y+2) / (y+2)^2*y^2(y-2)
3/y