SOLUTION: Please show work:
Divide
(fraction 1) (3y^2-12)/(^2+4y+4) / (y^3-2y^2)/(y^2+2y) (fraction 2)
Algebra.Com
Question 318214: Please show work:
Divide
(fraction 1) (3y^2-12)/(^2+4y+4) / (y^3-2y^2)/(y^2+2y) (fraction 2)
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
(3y^2-12)/(y^2+4y+4) / (y^3-2y^2)/(y^2+2y)
..
3(y^2-4)/(y+2)^2 / y^2(y-2)/y(y+2)
..
3(y+2)(y-2) /(y+2)^2 * y(y+2)/y^2(y-2)
..
3(y+2)(y-2)*y(y+2) / (y+2)^2*y^2(y-2)
3/y
RELATED QUESTIONS
Please can you help me with this equation?
3y^2-12 /4y^2+4y+4 divided by y^3-2y^2/... (answered by stanbon)
3y^3-2y[4y-y(y-3)]-[2y(y+1)-3y(y^2-1)]
(answered by Boreal)
Divide 3y^2-2y+1 by... (answered by MathLover1,ikleyn)
2/y+1=-4y/2y+2+3 (answered by Alan3354)
Simplify complety
2y^2+3y-14 / 4-y^2
/ means the fraction line... (answered by jim_thompson5910)
I had try this but I don't know if it is right
hopefully I'm writing it right so you... (answered by jim_thompson5910)
1). 2x/5 =4
2). y-12/y-5 = 2
[where / is fraction sign, not... (answered by solver91311)
Solve 4y ^2 = 12
I've done this and was wondering if I was on the right path:
4y ^2 (answered by JBarnum)
2y-3|5=1|2 |=fraction... (answered by Alan3354)