SOLUTION: Question: Evaluate: 1n(1/5sqrt e) (A) 1/5 (B) -1/5 (C) -5 (D) 5 Thank you!

Algebra.Com
Question 31748: Question: Evaluate: 1n(1/5sqrt e)
(A) 1/5
(B) -1/5
(C) -5
(D) 5
Thank you!

Answer by venugopalramana(3286)   (Show Source): You can put this solution on YOUR website!
Question: Evaluate: I SUPPOSE YOU MEAN.....PUT BRACKETS TO AVOID CONFUSION....1n((1)/(5sqrt e))=LN(1)-LN(5SQRT(E))=0-LN(5)-LN(E^0.5)
=-LN(5)-0.5LN(E)=-LN(5)-0.5...CHECK THE PROBLEM FOR PROPER TYPING
I THINK THE QUESTION IS LN(1/FIFTH ROOT OF E)
IT IS NOT SQUARE ROOT
IF NOTHING IS PUT IN V GROOVE OF THE SYMBOL IT IS SQUARE ROOT
IF 3 IS PUT IN V GROOVE OF THE SYMBOL IT IS CUBE ROOT
IF 4 IS PUT IN V GROOVE OF THE SYMBOL IT IS FOURTH ROOT
IF 5 IS PUT IN V GROOVE OF THE SYMBOL IT IS FIFTH ROOT...ETC....
I HOPE YOU KNOW 5 TH ROOT
IF 2*2*2*2*2=2^5=32
WE SAY 5TH.ROOT OF 32 =32^(1/5)= 32^0.2= 2...SO ASSUMING THAT WE GET
LN(1/FIFTH ROOT OF E)=LN(1/E^(1/5))=-LN(E^(1/5))=-(1/5)LN(E)=-1/5 IS THE ANSWER.
HENCE B IS THE ANSWER

RELATED QUESTIONS

The question is: Evaluate: 1n(1/5 sqrt e) Possible choices are: a. 1/5 b. -1/5 c.... (answered by mukhopadhyay)
Question reads like this: Evaluate: 1n(1/5sqrt3) Can you help??? Here are the... (answered by stanbon)
Evaluate the logarithm log4 1/1024 a.4 b.-5 c.-4 d.256... (answered by Tatiana_Stebko)
If a^2 + 4 < 4a + 9, then: a) a < -1 b) a > 5 c) a > -1 d) a < 5 e) -1 < a < 5... (answered by Edwin McCravy)
Can someone help me with the question below, I am lost. Thank you. Given A = {2, 4,... (answered by Edwin McCravy)
Could someone help me evaluate each expression? a. 27^1/3 b. (81^1/4)^4 c. (32^1/5) (answered by rfer)
evaluate : 8 - 5/3 a. 1/32 b.... (answered by Alan3354)
evaluate : 8 - 5/3 a. 1/32 b.... (answered by Alan3354)
d^2 - 10d + 25 A.(d-5)^2 B. (d+5)^2 c. (d-5)(d+5) d. (d-25)(d-1) Thank... (answered by ewatrrr)