SOLUTION: divide (x^3-3x^2-3)/(x-2)

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Question 314189: divide (x^3-3x^2-3)/(x-2)
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
First multiplier : x%5E2
x%5E2%2A%28x-2%29=x%5E3-2x%5E2
Subtract from the original polynomial to get the remainder,
%28x%5E3-3x%5E2-3%29-%28x%5E3-2x%5E2%29=-x%5E2-3
Next multiplier : -x
-x%28x-2%29=-x%5E2%2B2x
Subtract from the remainder to get the new remainder,
%28-x%5E2-3%29-%28-x%5E2%2B2x%29=-2x-3
Last multiplier:-2
-2%28x-2%29=-2x%2B4
Subtract from the remainder to get the new remainder,
%28-2x%2B4%29-%28-2x%2B4%29=-7
Put it all together with the final remainder,
%28x%5E3-3x%5E2-3%29%2F%28x-2%29=%28x%5E2-x-2%29-7%2F%28x-2%29