SOLUTION: (2s^-1T^3/6s^2T^-4)^-3 (That's 2s to the negative 1,t to the negative 3 over 6s to squared T to the power of negative 4 in parentheses and all of it to the power of negative

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Question 309197: (2s^-1T^3/6s^2T^-4)^-3
(That's 2s to the negative 1,t to the negative 3 over
6s to squared T to the power of negative 4 in parentheses
and all of it to the power of negative 3). I believe by other examples ^ is used as an "exponent" or power to equation and ( / ) is the same as a fraction. Sorry if I'm wrong, I'm still somewhat new to algebra.com.
Answer by ichudov(507)   (Show Source): You can put this solution on YOUR website!
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  • Graphical form: simplifies to
  • Text form: (2s^-1*T^3/(6s^2*T^-4))^-3 simplifies to 1/(T^(7)/s^3/3)^3
  • Cartoon (animation) form:
    For tutors: simplify_cartoon( (2s^-1*T^3/(6s^2*T^-4))^-3 )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at .
Remove unneeded parentheses around factor highlight_red%28+1%2F6+%29,highlight_red%28+1%2Fs%5E2+%29,highlight_red%28+1%2FT%5E-4+%29
It becomes .
Look at .
Factors 2 and 6 have greatest common factor (GCF) of 2. Reducing fraction.
It becomes .
Look at .
Reduce similar several occurrences of highlight_red%28+s%5E-1+%29 to highlight_green%28+s%5E%28-1-2%29+%29
It becomes .
Look at .
Reduce similar several occurrences of highlight_red%28+T%5E3+%29 to highlight_green%28+T%5E%283--4%29+%29
It becomes .
Look at .
Removed extra sign in front of -1
It becomes .
Look at .
Removed extra sign in front of 4
It becomes .
Look at .
Remove extraneous '1' from product highlight_red%28+1+%29
It becomes .
Look at .
Added fractions or integers together
It becomes .
Look at .
Added fractions or integers together
It becomes .
Look at .
Removed extra sign in front of -3
It becomes .
Look at .
Negative power changes multiplication to division
It becomes .
Look at .
Negative power changes multiplication to division
It becomes .
Look at .
Remove extraneous '1' from product highlight_red%28+1+%29
It becomes .
Result:

Universal Simplifier and Solver


Done!


nd that simplifies to

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