SOLUTION: logx + log(x-3)=1

Question 294210: logx + log(x-3)=1
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
1. Write as one log isolated on one side.
log[x(x - 3)] = 1
2. Write in exponential form.
Base = 10, exponent = 1
10^1 = x(x - 3)
3. Solve for x.
10 = x^2 - 3x
0 = x^2 - 3x - 10
0 = (x - 5)(x + 2)
Can you finish now?

RELATED QUESTIONS
log(x+3)=1-logx (answered by josmiceli)

log(x+3)=1-logx (answered by drk)

Log(x+2) - log(x-1) = logx -... (answered by ewatrrr)

solve: logx + log(x-3) = 1 (answered by jsmallt9)

log(x+3/10)+logx+1=0 (answered by jsmallt9)

solve: logx + log(x+3)=... (answered by nerdybill)

logx-log(x-1)=2 (answered by user_dude2008)

log(x-9)=1-logx (answered by jim_thompson5910)