SOLUTION: Find each value of x.
{{{2^log2^5=x}}}.
Algebra.Com
Question 278548: Find each value of x.
.
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
If this is what the problem really looks like then, since , this simplifies to:
Now we use our calculators to find log(32) and then use the calculators again to raise to to that power.
However, I suspect the the problem is actually:
This equation is extremely easy if you understand what logairthms are. Logarithms are exponents. In general, represents the exponent you put on a which results in b. This specific logarithm, , represents the exponent you put on 2 to get 5. And where do we see ? We see it as an exponent on 2! So , by the definition of logarithms, is 5!
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