SOLUTION: if {x^2-3x-40} divided by {x+5}
x^2-3x-40 divided by x+5
x^2-5x
-2x-40
-2x- 10
=30
x-2+30
x-30
I keep trying the problem to see were i made my mis
Algebra.Com
Question 266900: if {x^2-3x-40} divided by {x+5}
x^2-3x-40 divided by x+5
x^2-5x
-2x-40
-2x- 10
=30
x-2+30
x-30
I keep trying the problem to see were i made my mistake and i still can't seem to find were the error is?
Found 3 solutions by jim_thompson5910, josmiceli, JBarnum:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given expression.
Factor to get .
Factor to get .
Highlight the common terms.
Cancel out the common terms.
Simplify.
So simplifies to .
In other words, where
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
What do I multiply by to get ?
My first try is
subtract this from , I get
Now what do I add to to finish the division?
I'll try
I'll subtract this from
I get , so the division is finished with no remainder
The answer is
To prove it:
OK
Answer by JBarnum(2146) (Show Source): You can put this solution on YOUR website!
is same as so:
is the answer
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