SOLUTION: 4(2^x)+31(2^x)-8=0
Algebra.Com
Question 256102: 4(2^x)+31(2^x)-8=0
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given equation.
Let
Replace each term with 'z'
Combine like terms.
Add 8 to both sides.
Divide both sides by 35.
Plug in
Recall that can be rewritten as
Use the property shown above to rewrite the equation.
Rearrange the equation.
So the exact answer is which approximates to
RELATED QUESTIONS
x^2+14x-31=0 (answered by jim_thompson5910)
31=5-2(3x+4)-x (answered by unlockmath)
10+(x+2)=31
(answered by jim_thompson5910)
Find the function rule.
1. x| -3| -2| -1| 0| 1| 2| 3
f(x)| 10| 5| 2| 1| 2| 5| 10
(answered by Edwin McCravy)
(x-4)^2+8=0 (answered by josgarithmetic)
x/2+x/5+x/3=31 (answered by richwmiller)
1. 0.2(x+3)-4(2x-3)=3.4
2. x/2+ x/5+ x/3=31
(answered by checkley75)
Divide... (answered by rfer)
x^2+4y^-2x-3=0, 2x^2=z0x-y=41=0, 5x62-3y^2-30=0, x^2=y^2-12x=4y=31=0,... (answered by stanbon)