SOLUTION: find the inverse of log(base 2) (x^5) when i worked it out i got 2^x^5....but i didnt know if that could be simplified any further?

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: find the inverse of log(base 2) (x^5) when i worked it out i got 2^x^5....but i didnt know if that could be simplified any further?       Log On


   

Question 245000: find the inverse of log(base 2) (x^5)
when i worked it out i got 2^x^5....but i didnt know if that could be simplified any further?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Let y=log%282%2C%28x%5E5%29%29. Now swap x and y to get x=log%282%2C%28y%5E5%29%29. The goal here is to solve for y.


x=log%282%2C%28y%5E5%29%29 Start with the given equation.


2%5Ex=y%5E5 Convert to exponential form.


root%285%2C2%5Ex%29=y Take the 5th root of both sides to isolate 'y'


So the inverse is root%285%2C2%5Ex%29