SOLUTION: {{{2^(logx)=4*x}}}
I started with:
{{{2^(logx)=2^2*x}}}
then got:
Logx=2*x
don't know where to go from there
Algebra.Com
Question 244851:
I started with:
then got:
Logx=2*x
don't know where to go from there
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
Take the log of each side:
Subtract logx from each side:
Factor out the logx:
Divide both sides by (log2-1):
Finally, raise both sides as a power of 10:
.
This comes out to approximately .137609.
I checked this with a graphing calculator, and it is correct!!!
Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
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