SOLUTION: How do I do these? Solve the equation 9^x-1=(1/3)^2x Solve the equation 4^3x-1=1.5625x10^-2

Algebra.Com
Question 236404: How do I do these?
Solve the equation 9^x-1=(1/3)^2x
Solve the equation 4^3x-1=1.5625x10^-2

Answer by Earlsdon(6294)   (Show Source): You can put this solution on YOUR website!
Solve for x:
Substitute
Multiply the exponents on the left side.
Invert the right side and change the sign of the exponent.
Now since the bases (3) are equal, the exponents must be equal, so...
Add 2x to both sides.
Add 2 to both sides.
Divide both sides by 4.
Simplify.

RELATED QUESTIONS

how do i solve the equation 3 4 1 _ _ _ 2x - 3x =... (answered by Alan3354)
how do i solve the following equation for x: 2 - 4(3x + 1) = 8 -... (answered by checkley75,stanbon)
How do I solve for x on the following logrithmn equation: 1/2 log base 5(3x+4) = 1 (answered by stanbon!)
how do I solve these algebraic equations : 1/2x+6=-4 and... (answered by stanbon)
How do I solve the following equation? 2/3x + 1/2x =... (answered by rfer)
how do i solve the equation 3/5 x... (answered by checkley77)
how do you solve the equation 3x = 3(3x +... (answered by prabhjyot)
How do I solve the equation 3(x-1)+7 = 2(x+1)... (answered by harpazo)
1.)Solve the equation 2^(2x – 1) = 8^(x + 7). 2.)Solve the equation 3^x = 3^(3x + 1).... (answered by KMST)