SOLUTION: How would you solve the following equation by either factoring or the quadratic formula? {{{(2)^x+(1/2)^x=2}}} I got this far {{{(2^1)^x+(2^-1)^x=2}}} and I don't know wha

Algebra ->  Algebra  -> Exponential-and-logarithmic-functions -> SOLUTION: How would you solve the following equation by either factoring or the quadratic formula? {{{(2)^x+(1/2)^x=2}}} I got this far {{{(2^1)^x+(2^-1)^x=2}}} and I don't know wha      Log On

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Question 232172: How would you solve the following equation by either factoring or the quadratic formula?
%282%29%5Ex%2B%281%2F2%29%5Ex=2
I got this far
%282%5E1%29%5Ex%2B%282%5E-1%29%5Ex=2 and I don't know what else to do.

Answer by Alan3354(21557) About Me  (Show Source):
You can put this solution on YOUR website!
%282%29%5Ex%2B%281%2F2%29%5Ex=2
x = 0 works, but I don't see a method to solve this.