SOLUTION: Convert to logarithm form: 32^2/5=4

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Question 22662: Convert to logarithm form:
32^2/5=4
Found 2 solutions by longjonsilver, stanbon:
Answer by longjonsilver(2297) (Show Source):
You can put this solution on YOUR website!
What base of log do you want? Lets do it to base 10...i shall just write it as "log"...

(2/5)log32 = log4
2log32 = 5log4

Where do you want to take it?

To me, the 32 and 4 both SHOUT 2 at me..2^5 is 32 and 2^2 is 4, so we have:

which then becomes , which shows that the lefthand side is actually the SAME values as 4...no need to take logs

jon.

Answer by stanbon(48569) (Show Source):
You can put this solution on YOUR website!
A logarithm is just another name for an exponent.
The exponent in your problem is (2/5).
So you should 1st write:
log... = (2/5)
You are applying that exponent to some number or letter.
In your case that is the number 32. It is the base of
your logarithm statement.
So now you have this:
log(base32)... = (2/5)
When you apply the exponent to the base you get a number or a letter.
In your case that result is the number "4".
So now you have this:
log(base 32)4 = (2/5)
Hope this helps you do other log problems.
Cheers,
Stan H.