SOLUTION: I have spent about 4 or 5 hours trying to figure this out. I'm trying to identify the inverse function, "f^-1(x)", for the following question, "If f(x)=x^2/(x-1) what is f^-1(x)."

Algebra ->  Algebra  -> Exponential-and-logarithmic-functions -> SOLUTION: I have spent about 4 or 5 hours trying to figure this out. I'm trying to identify the inverse function, "f^-1(x)", for the following question, "If f(x)=x^2/(x-1) what is f^-1(x)."      Log On

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Question 22532: I have spent about 4 or 5 hours trying to figure this out. I'm trying to identify the inverse function, "f^-1(x)", for the following question, "If f(x)=x^2/(x-1) what is f^-1(x)." I have gotten to x^2=xy-y but have taken many paths from there and seem to be going in circles.
Answer by stanbon(48569) About Me  (Show Source):
You can put this solution on YOUR website!
That's fine so far.
Now interchange x and y to form the inverse.
y^2=yx-x
It's not very pretty but that is the inverse.
You would like to write that as y= something
but you can't. So leave it as it is.
You could have done that interchance on the original
form of the equation and just left it that way.
Cheers,
Stan H.