# SOLUTION: Hello, I am solving some questions in my textbook and I have seem to fallen into a slump. Please help. A bacteria called escherichia coli are commonly found in the bladder.

Algebra ->  Algebra  -> Exponential-and-logarithmic-functions -> SOLUTION: Hello, I am solving some questions in my textbook and I have seem to fallen into a slump. Please help. A bacteria called escherichia coli are commonly found in the bladder.       Log On

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 Question 22250: Hello, I am solving some questions in my textbook and I have seem to fallen into a slump. Please help. A bacteria called escherichia coli are commonly found in the bladder. Suppose that 3000 of the bacteria are present at time t=0. Then t minutes later, the number of bacteria present can be approximated by n(t)=3000(2)^(t/20) (the t/20 is written in exponent form) How many bacteria will be present after 10min? 20min? 30min? 40min? 60min? If I could have someone workout the first few and I can probably get the rest done. Answer by stanbon(57203)   (Show Source): You can put this solution on YOUR website!Your equation says: #of bacteria at time "t" is n(t) = 3000(2)^(t/20) By the way this means the number doubles every 20 minutes. n(10)=3000 (2)^(10/20) n(10)=3000 (2)^(1/2) n(10)=3000 (sqrt 2) n(10)=4242.64.... So you see you have to substitute 20 or 30 or 40 or 60 into the formula in place of the "n". Cheers, Stan H.