SOLUTION: log (base 5)x+ log (base5) (x+4)= log (base 5) 5

Algebra ->  Algebra  -> Exponential-and-logarithmic-functions -> SOLUTION: log (base 5)x+ log (base5) (x+4)= log (base 5) 5      Log On

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Question 21975: log (base 5)x+ log (base5) (x+4)= log (base 5) 5
Answer by Alwayscheerful(414) About Me  (Show Source):
You can put this solution on YOUR website!
Rewritten, your question equation is:
log[5]x +log[5]x+4=log[5]5
**NUMBER IN BRACKET IS THE BASE OF THE LOGARITHM**
I'm assuming your question is "solve for x"
Well, the first law of logarithms is:
log[a]x+log[a]y=log[a]xy
So, in your case
x%2Ay=5
log[5]x(x+4)=log[5]5
log[5]x^2+4=log[5]5
x%5E2%2B4+=5
x%5E2=1
highlight%28x=1%29
Hope this helps!