SOLUTION: log base3 x +log base3 (x-4) +16=18
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Question 21665: log base3 x +log base3 (x-4) +16=18
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Solve for x:
log(x)+log(x-4)+16 = 18 Subtract 16 from both sides.
log(x)+log(x-4) = 2 Apply the product rule for logarithms:LogM+logN = log(MN)
log(x)+log(x-4) = log(x^2-4x) = 2 Rewrite in exponential form:
logx = y means so:
log(x^2-4x) = 2 means Subtract 3^2 = 9 from both sides.
Solve using the quadratic formula:
=
The roots are:
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