SOLUTION: Simply: ln(e^2k)
Algebra.Com
Question 202851: Simply: ln(e^2k)
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
Remember ln(e) =1,,,,,lna^b=blna
.
lne^(2k) = 2k *ln(e) = 2k*(1) = 2k
.
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