SOLUTION: write an equation for the line that contains the point (4,-1) and is perpendicular to the equation y= -2/3x + 7

Question 197740: write an equation for the line that contains the point (4,-1) and is perpendicular to the equation y= -2/3x + 7
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
Remember y=mx+b,,,,and perpendicular lines have slopes that are negative reciprocals
.
y= ( -2/3 ) x +7
.
slope is -2/3,,,,,slope in perpendicular line is ( +3/2)
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y= 3/2 x +b
.
at ( 4,-1)
.
(-1) = 3/2 (4) +b
.
-1 -6 = b
.
-7 = b
.
Inserting in y=mx+b,,,,,y= 3/2 x -7
.
checking
substitute ( 4, -1) into y = 3/2 x -7
-1 = (3/2)(4) -7 = -1 ,,,,ok
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