SOLUTION: write an equation for the line that contains the point (7,0) and is perpendicular to the equation y= -12x

SOLUTION: write an equation for the line that contains the point (7,0) and is perpendicular to the equation y= -12x - 8

Question 197734: write an equation for the line that contains the point (7,0) and is perpendicular to the equation y= -12x - 8
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
first we must find the slope of the equation y=-12x-8......since this is in point slope form....we can see the slope is -12. now we know that any line perpendicular to this line will have a slope that is the negative reciprical of it.....the negative reciprical of -12 is 1/12
:
now we have the slope and a point (7,0)...using the point slope formula we have
:
y-0=(1/12)(x-7)
:
y=(1/12)x-7/12 or in standard form multiply all terms by 12
:
12y=x-7--->x-12y=7(standard form)
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