SOLUTION: I need help solving this 3^x=40

Algebra.Com
Question 194615: I need help solving this 3^x=40
Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
3^x=40
log[3](3^x)=log[3]40
x=log[3]40
x=ln(40)/ln(3)
x=3.6889.../1.0986
x=3.3578...
.
Ed

RELATED QUESTIONS

i need help solving this :... (answered by rfer)
I need help on solving this equation? (2x)/(x+3)+5=(3)/(x+3) (answered by Mathtut)
I need help solving this equation: 1/3(x+9)+5 =... (answered by Fombitz)
i need help solving this: ((( 8/(x+3)>1/(x+3)... (answered by stanbon)
I need help solving this problem: X-2 X-1 ___ = _____ X-3... (answered by longjonsilver)
I need help solving this problem: X-2 X-1 ___ = _____ X-3... (answered by longjonsilver,Pieter)
I need help solving this question -2=10b-... (answered by northwest_husky_babe)
I need help solving this question -2=10b-... (answered by rchill)
I need help solving this question -2=10b-... (answered by rchill)