SOLUTION: log2y=1/3log227
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Algebra: Exponent and logarithm as functions of power
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Question 193187
This question is from textbook
Algerbra 2
:
log2y=1/3log227
This question is from textbook
Algerbra 2
Answer by
Alan3354(21611)
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log2y=1/3log227
-------------------
log(2y) = log(cube root(227))
2y = cube root(227) = ~ 6.1
y = 3.05