SOLUTION: log3x+log(x+2)=1

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Question 192261: log3x+log(x+2)=1
Answer by nerdybill(7384)   (Show Source): You can put this solution on YOUR website!
log3x+log(x+2)=1
log3x(x+2)=1
3x(x+2)=10^1
3x^2+6x=10
3x^2+6x-10=0
Solving the above using the quadratic equation yields two solutions:
x = {1.082, -3.082}
.
Details of quadratic follows:
.
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=156 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 1.08166599946613, -3.08166599946613. Here's your graph:
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