SOLUTION: i need help on this problem. i am supposed to solve the equation and check for extraneous solutions. i worked it out but i did not get the right answer. i need help finding the rea

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Question 187844: i need help on this problem. i am supposed to solve the equation and check for extraneous solutions. i worked it out but i did not get the right answer. i need help finding the real one.

3^(x^2)=1
log3(x^2)=log1
x^2log3=log1
x^2=log1/log3
x^2=o
x= square root of 0
x=o

Found 2 solutions by Alan3354, jim_thompson5910:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
i need help on this problem. i am supposed to solve the equation and check for extraneous solutions. i worked it out but i did not get the right answer. i need help finding the real one.
3^(x^2)=1
log3(x^2)=log1
x^2log3=log1
x^2=log1/log3
x^2=0
x= square root of 0
x=0
---------------
check the answer.
(3^(x^2)) + 5 = 6
3^0 + 5 = 6
1 + 5 = 6
6 = 6 Must be right.

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
If that is the correct equation, then you have the right answer.

Check:

Start with the given equation.


Plug in


Square 0 to get 0


Raise 3 to the zeroth power to get 1


Add. Since the equation is true, this verifies the answer


So either the book has the wrong answer or there's a typo in the problem.

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