SOLUTION: Find the solution to the equation 8^(4x+1)=16^(4x+2)

Algebra.Com
Question 183591: Find the solution to the equation
8^(4x+1)=16^(4x+2)

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Find the solution to the equation
8^(4x+1)=16^(4x+2)
(2^3)^(4x+1) = (2^4)^(4x+2)
2^(12x+3) = 2^(16x+8)
Equate the exponents to get:
12x+3= 16x+8
4x = -5
x = -5/4
============
Cheers,
Stan H.

RELATED QUESTIONS

Find the solution 4x^2 + 8 =... (answered by Alan3354)
Solve: 8^(4x-3)= 1/16, find the exact... (answered by venugopalramana,josmiceli)
Is the solution to an equivalent equation not with fractions for 1/4x - 3 = 2/5 , 5x - 60 (answered by Edwin McCravy)
Determine whether each ordered pair is a solution of the given equation. y=8-4x... (answered by malakumar_kos@yahoo.com)
Is the equation 4x-1=16... (answered by elima,khwang)
What is the solution to the equation? (-9x+5)^1/2 =... (answered by stanbon)
Find the solutions to the equation below. Check all that apply. 4x^2 + 4x + 1 =... (answered by sofiyac)
Find the solution to the system of equation below 4x + 7y = -1 x + y =... (answered by ben720)
Solve the following equation and check your solution... (answered by MathLover1)