SOLUTION: Thank you in advance for helping me with this problem. (4^x)(16^3x-1)=8 This is what I have done. (2^2x)(2^4(3x-1))=2^3 in the end I got 2/7??? am I on the right track? thank

Question 176826This question is from textbook college algebras
: Thank you in advance for helping me with this problem. (4^x)(16^3x-1)=8
This is what I have done.
(2^2x)(2^4(3x-1))=2^3
in the end I got 2/7??? am I on the right track? thanks for your help.

This question is from textbook college algebras

Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Solve for x:
Your first step is good!
Expand the second exponent.
The second factor on the left shows the exponents being subtracted so this means division:
Multiply both sides by
Perform the indicated multiplication by adding the exponents.
The bases (2) are equal so the exponents are equal.
Divide both sides by 14.

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