# SOLUTION: 8X^3y^6+27

Algebra ->  Algebra  -> Exponential-and-logarithmic-functions -> SOLUTION: 8X^3y^6+27      Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Algebra: Exponent and logarithm as functions of power Solvers Lessons Answers archive Quiz In Depth

 Question 175719: 8X^3y^6+27Found 2 solutions by EMStelley, nerdybill:Answer by EMStelley(187)   (Show Source): You can put this solution on YOUR website!I believe what you are asking is to factor Notice that each term can be written using cubes. So we have that Now, the sum of cubes can be factored as following: So, here and b=3 Simplified, this is Answer by nerdybill(6958)   (Show Source): You can put this solution on YOUR website!I'm assuming you're asked to factor the expression. . Starting with: 8X^3y^6+27 . Notice, I can rewrite the above as: (2xy^2)^3+(3)^3 . Now, it is a "sum of cubes" -- a special factor... where: a^3 + b^3 = (a + b)(a^2 – ab + b^2) . In your case, a = 2xy^2 b = 3 . Plugging the above into: a^3 + b^3 = (a + b)(a^2 – ab + b^2) we get: (2xy^2)^3 + 3^3 = (2xy^2 + 3)((2xy^2)^2 – 3(2xy^2) + 3^2) (2xy^2)^3 + 3^3 = (2xy^2 + 3)(4x^2y^4 – 6xy^2 + 9)