SOLUTION: square root(x+8) = square root(2x+7)-5 this is what i've gotten so far. 1. (x+8)=2x+32-10squareroot(2x+7) 2. -x-24=-10squareroot(2x-7) 3. x^2 - 200x -124=0 4. quadratic equ

Algebra ->  Algebra  -> Exponential-and-logarithmic-functions -> SOLUTION: square root(x+8) = square root(2x+7)-5 this is what i've gotten so far. 1. (x+8)=2x+32-10squareroot(2x+7) 2. -x-24=-10squareroot(2x-7) 3. x^2 - 200x -124=0 4. quadratic equ      Log On

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Question 175674: square root(x+8) = square root(2x+7)-5
this is what i've gotten so far.
1. (x+8)=2x+32-10squareroot(2x+7)
2. -x-24=-10squareroot(2x-7)
3. x^2 - 200x -124=0
4. quadratic equation outcomes are 200.6180898 and -.6180898248.
is that right?
Answer by stanbon(57285) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt(x+8) = sqrt(2x+7) - 5
Square both sides to get:
x+8 = 2x+7 - 10sqrt(2x+7) + 25
10sqrt(2x+7) = x + 24
Square both sides to get:
2x+7 = x^2 + 48x + 576
x^2 + 46x + 569 = 0
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This quadratic has no Real Number solutions.
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Cheers,
Stan H.