# SOLUTION: square root(x+8) = square root(2x+7)-5 this is what i've gotten so far. 1. (x+8)=2x+32-10squareroot(2x+7) 2. -x-24=-10squareroot(2x-7) 3. x^2 - 200x -124=0 4. quadratic equ

Algebra ->  Algebra  -> Exponential-and-logarithmic-functions -> SOLUTION: square root(x+8) = square root(2x+7)-5 this is what i've gotten so far. 1. (x+8)=2x+32-10squareroot(2x+7) 2. -x-24=-10squareroot(2x-7) 3. x^2 - 200x -124=0 4. quadratic equ      Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Algebra: Exponent and logarithm as functions of power Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Exponential-and-logarithmic-functions Question 175674: square root(x+8) = square root(2x+7)-5 this is what i've gotten so far. 1. (x+8)=2x+32-10squareroot(2x+7) 2. -x-24=-10squareroot(2x-7) 3. x^2 - 200x -124=0 4. quadratic equation outcomes are 200.6180898 and -.6180898248. is that right?Answer by stanbon(57285)   (Show Source): You can put this solution on YOUR website!sqrt(x+8) = sqrt(2x+7) - 5 Square both sides to get: x+8 = 2x+7 - 10sqrt(2x+7) + 25 10sqrt(2x+7) = x + 24 Square both sides to get: 2x+7 = x^2 + 48x + 576 x^2 + 46x + 569 = 0 ---- This quadratic has no Real Number solutions. ------- Cheers, Stan H.