SOLUTION: a chunk of radioactive material decays from a mass of 450 grams to 165 grams in two weeks,(14 days). find the half life time and the amount of material left after 70 days

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: a chunk of radioactive material decays from a mass of 450 grams to 165 grams in two weeks,(14 days). find the half life time and the amount of material left after 70 days      Log On


   



Question 173139: a chunk of radioactive material decays from a mass of 450 grams to 165 grams in two weeks,(14 days). find the half life time and the amount of material left after 70 days
Answer by Edwin McCravy(20086) About Me  (Show Source):
You can put this solution on YOUR website!
a chunk of radioactive material decays from a mass
of 450 grams to 165 grams in two weeks,(14 days).

The exponential equation to use is:
A=+Pe%5E%28r%2At%29, where
A = Amount, in grams
t = time, in days
r = a constant
P = a constant

When t+=+0 days, A+=+450 grams, therefore
(t,A) = (0,450) is a point on the graph.

When t+=+14 days, A+=+165 grams, therefore 
(t,A) = (14,165) is another point on the graph.
 
Substitute the first point in the equation:

A=+Pe%5E%28r%2At%29

450=+Pe%5E%28r%2A0%29%29

450=Pe%5E0

450=P%281%29

450+=+P

So we have found that P is the original amount
Substitute the second point in the equation:

A=+450e%5E%28r%2At%29

165=+450e%5E%28r%2A14%29

165=+450e%5E%2814r%29

Divide both sides by 450:

165%2F450=+%28450e%5E%2814r%29%2F450%29

11%2F30+=+e%5E%2814r%29

Use the fact that Y=e%5EX is equivalent to X=ln%28Y%29
to rewrite the equation in natural log form:

14r=ln%2811%2F30%29

Divide both sides by 14

r=ln%2811%2F30%29%2F14

Get your calculator and find the right side:

r+=+-.0716644363

Substitute -.0716644363 for r in

A=+450e%5E%28r%2At%29

A=+450e%5E%28-.0716644363%2At%29

Now we can do the last two parts:

>>...find the half life time...<<

This asks us to find the time it takes
for the original 450 grams to reduce to
just half of that amount or 225 grams
(half of 450 grams)

So we substitute 225 for A in

A=+450e%5E%28-.0716644363%2At%29

225=+450e%5E%28-.0716644363%2At%29

Divide both sides by 450:

225%2F450=+%28450e%5E%28-.0716644363%2At%29%29%2F450

1%2F2+=+e%5E%28-.0716644363%2At%29

Again use the fact that Y=e%5EX is equivalent to 
X=ln%28Y%29 to rewrite the equation in natural 
log form:

%28-.0716644363%2At%29=ln%281%2F2%29

divide both sides by -.0716644363

%28-.0716644363%2At%29%2F%28-.0716644363%29=ln%281%2F2%29%2F%28-.0716644363%29

t=ln%281%2F2%29%2F%28-.0716644365%29

Get your calculator and find the right side:

t=9.672122128

So, it takes about 9.7 days for the radioactive
material to reduce from its original amount
of 450 grams to half its original amount, or
225 grams.

Now the last part:

>>...and the amount of material left after 70 days...<<

All we have to do is substitute 70 for t in

A=+450e%5E%28-.0716644363%2At%29

A=+450e%5E%28-.0716644363%2A70%29

A+=+450e%5E%28-5.016510544%29

A+=+2.982425926

So after 70 days, there is only about 3 grams
remaining.

Edwin