SOLUTION: I need help getting started the equation is 2^3x-4=64

Algebra.Com
Question 170666: I need help getting started the equation is 2^3x-4=64
Answer by midwood_trail(310)   (Show Source): You can put this solution on YOUR website!
2^3x-4=64
Before anyone can this, we need to know what is the given exponent.
In other words, is the given exponent 3x or (3x - 4)?
Write back and I'll help you.



RELATED QUESTIONS

I need help solving the following... I have to simplify and then solve using the... (answered by Alan3354,jorel1380)
How do I factor by grouping? 7x^3-28x^2-3x+12 I started by (7x^3-28x^2)+(-3x+12)... (answered by jim_thompson5910)
i need help with this two part question we started slope and i am lost and getting... (answered by ewatrrr,Alan3354,lynnlo,Edwin McCravy)
I need help solving these equations- the last two I need to solve and graph. getting... (answered by edjones)
I need help with this particular question. sec H= 25/24 and angle H is in QIV. Find tan (answered by ewatrrr)
What is the discriminant of (3x+2)x=4-2x? I think the answer is 64 but I need an... (answered by ilana)
For each function, find the indicated values. f(x)=2x-5 I just need help getting... (answered by Fombitz)
Write the equation in log form: 2^2=4. I understand the question, but need help... (answered by jim_thompson5910)
I need help completing the square of a quadratic equation. ] (3x^2)+(x)-(1/2)=0... (answered by ankor@dixie-net.com)