# SOLUTION: A bacteria culture starts with 120 bacteria and after three hours the population consists of 200 bacteria. assuming that the culture grows exponentially, find the poplation after 5

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 Click here to see ALL problems on Exponential-and-logarithmic-functions Question 170404: A bacteria culture starts with 120 bacteria and after three hours the population consists of 200 bacteria. assuming that the culture grows exponentially, find the poplation after 5 hours.Answer by stanbon(57246)   (Show Source): You can put this solution on YOUR website!A bacteria culture starts with 120 bacteria and after three hours the population consists of 200 bacteria. assuming that the culture grows exponentially, find the poplation after 5 hours. --------------------------------------------------- A(t) = ab^t --------------------- 200 = 120b^3 b^3 = 200/120 = 5/3 b = 1.047197551.... ----------- Equation: A(5) = 120(1.047197551)^5 A(5) = 151.12 Rounding down, A(5) = 151 ============================= Cheers, Stan H.