SOLUTION: Can someone please explain how to solve the following problem. Your assistance is greatly appreciated! Express in terms of sums and differences of logarithms log square root of x

Question 170275: Can someone please explain how to solve the following problem. Your assistance is greatly appreciated!
Express in terms of sums and differences of logarithms
log square root of x^4/yz

Found 2 solutions by Alan3354, Earlsdon:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
log square root of x^4/yz
= log(sqrt(x^4/yz))
= log(x^2*sqrt(1/yz))
= 2*log(x) + 1/2log(1/yz)
= 2*log(x) - 1/2log(yz)
= 2log(x) - 1/2(log(y) -1/2log(z)

Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Express in terms of sums or differences:
Rewrite the square root as an exponent:
Apply the "power" rule.
Now apply the "quotient" rule.
You can apply the "power" rule again to the first log.
Now apply the "product" rule to the second logarithm.
Finally, multiply through by 1/2 to simplify.
and this can also be written as:

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