SOLUTION: I need lots of help with my homework. We are going over the laws of exponents. I understand most of it. Just not problems where you have to divide and the base number is larger on

Question 167477This question is from textbook Practice Workbook
: I need lots of help with my homework. We are going over the laws of exponents. I understand most of it. Just not problems where you have to divide and the base number is larger on top than on bottom.
My problem is:
12m^8y^6
_________
-9my^4
(^=power) This question is from textbook Practice Workbook

Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
12m^8y^6
---------
-9my^4
.
First look at the coefficients (12/-9). This can be reduced by dividing numerator and denominator by 3:
4m^8y^6
---------
-3my^4
.
Now, look at the 'm's -- m^8= mmmmmmmm (eight m's on the top) and one 'm' on the bottom (denominator). You cancel ONE of the m's leaving:
4m^7y^6
---------
-3y^4
.
Finally looking at the 'y's -- 6 y's on the numerator and 4 y's on the denominator -- you can cancel four y's from top and bottom:
4m^7y^2
---------
-3
.
That's it. You cannot reduce any further.
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