SOLUTION: The Last problem for the summer 25^(x+2)=5^(3x-4) I think you take like 5 out and make 5 5 so then its 5x+2=3x-4 then maybe 2x=-2 then divide by two so x is negative one but

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: The Last problem for the summer 25^(x+2)=5^(3x-4) I think you take like 5 out and make 5 5 so then its 5x+2=3x-4 then maybe 2x=-2 then divide by two so x is negative one but      Log On


   

Question 154591: The Last problem for the summer
25^(x+2)=5^(3x-4)
I think you take like 5 out and make 5 5
so then its 5x+2=3x-4 then maybe 2x=-2 then divide by two so x is negative one but i think its wrong any help guys?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
25^(x+2)=5^(3x-4)
(5^2)^(x+2) = 5^(3x-4
2x+4 = 3x-4
x = 8
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Cheers,
Stan H.