SOLUTION: The Last problem for the summer 25^(x+2)=5^(3x-4) I think you take like 5 out and make 5 5 so then its 5x+2=3x-4 then maybe 2x=-2 then divide by two so x is negative one but

SOLUTION: The Last problem for the summer 25^(x+2)=5^(3x-4) I think you take like 5 out and make 5 5 so then its 5x+2=3x-4 then maybe 2x=-2 then divide by two so x is negative one but

Algebra.Com

Question 154591: The Last problem for the summer
25^(x+2)=5^(3x-4)
I think you take like 5 out and make 5 5
so then its 5x+2=3x-4 then maybe 2x=-2 then divide by two so x is negative one but i think its wrong any help guys?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
25^(x+2)=5^(3x-4)
(5^2)^(x+2) = 5^(3x-4
2x+4 = 3x-4
x = 8
===========
Cheers,
Stan H.
RELATED QUESTIONS
I need help using the substitution method so can you help me solve this problem:... (answered by sdmmadam@yahoo.com)

Why is this wrong? Problem#: 12- Solve each exponential equation by expressing each... (answered by checkley75)

Please tell me if my process is right or wrong. lim x->-∞... (answered by Fombitz)

Alrighty, here is the question, 6 _____ 3+ sqrt 5 , I... (answered by jim_thompson5910)

Im having trouble with some word problems i have many for my homework i understand the... (answered by stanbon,lwsshak3)

Hi, me and my friends are having troubling graphing 4|3x+5|+2=10 for our summer... (answered by Fombitz)

how do i solve system of equations? that look like these... (answered by ReadingBoosters)

Simplify (rationalize all denominators) x^(3/4) + 5/[x^(1/4)] (you may assume x>0) (answered by stanbon)

I�m supposed to solve the below expression for X, but I can�t figure out what I�m doing... (answered by jim_thompson5910)